AD8333 Data Sheet
Rev. E | Page 22 of 32
As previously noted, a typical CW signal has a large dc and
very low frequency component compared with its desired low
CW Doppler baseband frequency, and another unwanted
component at the 2 × LO. The dc component flows through the
gain resistors R1x, and the 2 × LO flows through the capacitors
C1x. The smaller desired CW Doppler baseband signal is in the
frequency range of 1 kHz to 50 kHz.
Because the output current of the AD8333 contains the baseband
frequency, a dc component, and the 2 × LO frequency voltages,
the desired small amplitude baseband signal must be extracted
after a series of filters. These are shown in Figure 55 as LPFnA,
HPFnA, and gain stages.
Before establishing the value of CLPF1, the resistor RLPF1 is
selected based on the peak operating current and the linear
range of the op amp. Because the peak current for each AD8333
is 6.6 mA and there are eight channels to be summed, the total
peak current required is 52.8 mA. Approximately half of this
current is dc, and the other half is at a frequency of 2 × LO.
Therefore, about 26.4 mA flows through the resistor, and the
remaining 26.4 mA flows through the capacitor. R1 was selected
as 100 Ω and, after filtering, generates a peak dc and very low
frequency voltage of 2.64 V at the AD8021 output. For power
supplies of ±5 V, 100 Ω is a good choice for R1.
However, because the CW signal needs to be amplified as
much as possible and the noise degradation of the signal path
minimized, the value of R1 should be as large as possible. A
larger supply helps in this regard, and the only factor limiting
the largest supply voltage is the required power.
For a ±10 V supply on the AD8021, R1 can be increased to
301 Ω to realize the same headroom as with a ±5 V supply. If a
higher value of R1 is used, C1 must be adjusted accordingly (in
this example, 1/3 the value of the original value) to maintain the
desired LPF roll-off. The principal advantage of a higher supply
is greater dynamic range, and the trade-off is power consumption.
The user must weigh the trade-offs associated with the supply
voltage, R1, C1, and the following circuitry. A suggested design
sequence is as follows:
1. Select a low noise, high speed op amp. The spectral density
noise (en) should be <2 nV/√Hz, and the 3 dB bandwidth
should be ≥3× the expected maximum 2 × LO frequency.
2. Divide the maximum linear output current by 6.6 mA to
determine the maximum number of AD8333 channels that
can be summed.
3. Select the largest value of R1 that permits the output
voltage swing within the power supply rails.
4. Calculate the value of C1 to implement the LPF corner that
allows the CW Doppler signal to pass with maximum
attenuation of the 2 × LO signal.
The filter LPF1A establishes the upper frequency limit of the
baseband frequency and is selected well below the 2 × LO
frequency, typically 100 kHz or less (for example, 88 kHz in
Figure 55).
A useful equation for calculating C1 is
(1)
As previously mentioned, the AD8333 output current contains a
dc current component. This dc component is converted to a
large dc voltage by the AD8021 LPF. Capacitor C2 filters this dc
component and, with R2 + R3, establishes a high-pass filter with
a low frequency cutoff of about 100 Hz. Capacitor C3 is much
smaller than C2 and, consequently, can be neglected. C2 can be
calculated by
(2)
To achieve maximum attenuation of the 2 × LO frequency, a
second low-pass filter, LPF2, is established using the parallel
combination of R2 and R3, and C3. Its −3 dB frequency is
3)||(2
1
2CR3R2
fLPF π
= (3)
In the example shown in Figure 55, fLPF2 = 81 kHz.
Finally, the feedback resistor of the AD797 must be calculated.
This is a function of the input current (number of channels)
and the supply voltage.
The second-order summing amplifier requires a very low noise
op amp, such as the AD797, with 0.9 nV/√Hz, because the
amplifier gain is determined by Feedback Resistor R4 divided
by the parallel combination of the LPF2A resistors seen looking
back toward the AD8021s. Referring to Figure 55, the AD797
in-band (100 Hz to 88 kHz) gain is expressed as
[ ]
)(||)( R2BR2BR3AR2A
R4
++
(4)
The AD797 noise gain can increase to unacceptable levels
because the denominator of the gain equation is the parallel
resistance of all the R2 + R3 resistors in the AD8021 outputs.
For example, for a 64-channel beamformer, the resistance seen
looking back toward the AD8021s is about 1.4 kΩ/8 = 175 Ω.
For this reason, the value of (R2x + R3x) should be as large as
possible to minimize the noise gain of the AD797. (Note that
this is the case for the AD8021 stages because they look back
into the high impedance current sources of the AD8333s.)
Due to these considerations, it is advantageous to increase the
gain of the AD8021s as much as possible because the value of
(R2x + R3x) can be increased proportionally. Resistors (R2x +
R3x) convert the CW voltages to currents that are summed at
the inverting inputs of the AD797 op amp, and then amplified
and converted to voltages by R4.