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W ide Input Voltage Range, High Ef ficiency
Fault Tolerant LED Driver
A8513
17
Allegro MicroSystems, Inc.
115 Northeast Cutoff
Worcester, Massachusetts 01615-0036 U.S.A.
1.508.853.5000; www.allegromicro.com
Design Example
This section provides a method for selecting component values
when designing an application using the A8513. A typical circuit
using this design is shown in figure 21.
Assumptions: For the purposes of this example, the following are
given as the application requirements:
• VIN: 5 to 16 V
• Quantity of series LEDs, #SERIESLEDS: 6
• LED current, ILED: 120 mA
• Vf at 120 mA: 3.2 V
• fSW: 2 MHz
• TA(max): 85°C
• PWM dimming frequency: 200 Hz with a minimum duty cycle
of 1%.
Procedure: Select the appropriate configuration and the individual
component values in an ordered sequence.
Step 1: Connect the series LED string from VOUT to the LED
pin.
Step 2: Determine the value for the ILED setting resistor, RISET
:
RISET = VISET × AISET/ ILED (7)
= (1.003 × 1045) / 120 mA = 8.74 k
Choose an 8.66 k resistor.
Step 3: Determine the values of the OVP resistors. The OVP
resistors are connected between the OVP pin and the output volt-
age (VOUT) and the OVP pin and ground.
Step 3a: The first step is to determine the maximum voltage
based on the LED Vf requirements. To this value the regulation
voltage should be added, as well as another 2 V to account for
noise, output ripple, and resistor tolerances. The regulation volt-
age, VLED
, of the A8513 is 880 mV. Then:
VOUT(OVP) = #SERIESLEDS × Vf + VLED + 2 V (8)
= 6 × 3.2 V+ 0.880 V + 2 V
= 22.08 V
To find the OVP resistor values, the user should choose a resis-
tor divider that has very low current (IOVP) and ROVP should be
approximately 1 M. A good starting point is 50 A as IOVP .
(The IOVP current is used later in calculating the total leakage
current.) Then
:
ROVP1 = (VOUT(OVP) – VOVPHI(th) ) / IOVP (9)
= (22.08 V – 1.218 V) / 50 A = 417.2 k
and:
ROVP2 = VOVPHI(th) / IOVP (10)
= 1.218 V / 50 A = 24.36 k
Choose a value of resistor that is higher value than the calculated
ROVP . In this case 422 k was selected. Below is the actual value
of the minimum OVP trip level with the selected resistor:
VOUT(OVP) = ROVP × IOVP × VOVPHI(th) (11)
= 422 k × 50 A + 1.218 V = 22.32 V
STEP 3b: At this point a quick check should be done to determine
if the conversion ratio is acceptable for the selected frequency:
Dmaxofboost = 1 – tSW(OFF) × fSW (12)
= 1 – 85 ns × 2 MHz = 83%
where the Minimum Switch Off-Time, tSW(OFF) , is found in the
Electrical Characteristics table.
The Theoretical Maximum VOUT is then calculated as:
VOUT(max) Vd
=–
1 – Dmaxofboost
VIN(min)
0.4 V 29.01 V
==–
1 – 0.83
5 V
(13)
where Vd is the diode forward voltage.
The Theoretical Maximum VOUT value must be greater than the
value VOUT(OVP) . If this is not the case, a lower frequency ver-
sion of the A8513 should be chosen to meet the maximum duty
cycle requirements.
Step 4: Inductor selection. The inductor should be chosen such
that it can handle the necessary input current. In most applica-
tions, due to stringent EMI requirements, the system must operate
in continuous conduction mode throughout the whole input volt-
age range.