Application Information (Continued)
0.5% to 3% of the output voltage. To obtain low ripple
voltage, the ESR of the output capacitor must be low, how-
ever, caution must be exercised when using extremely low
ESR capacitors because they can affect the loop stability,
resulting in oscillation problems. If very low output ripple
voltage is needed (less than 20 mV), a post ripple filter is
recommended (See Figure 1). The inductance required is
typically between 1 µH and 5 µH, with low DC resistance, to
maintain good load regulation. A low ESR output filter ca-
pacitor is also required to assure good dynamic load re-
sponse and ripple reduction. The ESR of this capacitor may
be as low as desired, because it is out of the regulator
feedback loop. The photo shown in Figure 20 shows a
typical output ripple voltage, with and without a post ripple
filter.
When observing output ripple with a scope, it is essential
that a short, low inductance scope probe ground connection
be used. Most scope probe manufacturers provide a special
probe terminator which is soldered onto the regulator board,
preferable at the output capacitor. This provides a very short
scope ground thus eliminating the problems associated with
the 3 inch ground lead normally provided with the probe, and
provides a much cleaner and more accurate picture of the
ripple voltage waveform.
The voltage spikes are caused by the fast switching action of
the output switch, the diode, and the parasitic inductance of
the output filter capacitor, and its associated wiring. To mini-
mize these voltage spikes, the output capacitor should be
designed for switching regulator applications, and the lead
lengths must be kept very short. Wiring inductance, stray
capacitance, as well as the scope probe used to evaluate
these transients, all contribute to the amplitude of these
spikes.
When a switching regulator is operating in the continuous
mode, the inductor current waveform ranges from a triangu-
lar to a sawtooth type of waveform (depending on the input
voltage). For a given input and output voltage, the peak-to-
peak amplitude of this inductor current waveform remains
constant. As the load current increases or decreases, the
entire sawtooth current waveform also rises and falls. The
average value (or the center) of this current waveform is
equal to the DC load current.
If the load current drops to a low enough level, the bottom of
the sawtooth current waveform will reach zero, and the
switcher will smoothly change from a continuous to a discon-
tinuous mode of operation. Most switcher designs (irregard-
less how large the inductor value is) will be forced to run
discontinuous if the output is lightly loaded. This is a per-
fectly acceptable mode of operation.
In a switching regulator design, knowing the value of the
peak-to-peak inductor ripple current (∆I
IND
) can be useful for
determining a number of other circuit parameters. Param-
eters such as, peak inductor or peak switch current, mini-
mum load current before the circuit becomes discontinuous,
output ripple voltage and output capacitor ESR can all be
calculated from the peak-to-peak ∆I
IND
. When the inductor
nomographs shown in Figure 4 through 7are used to select
an inductor value, the peak-to-peak inductor ripple current
can immediately be determined. The curve shown in Figure
21 shows the range of (∆I
IND
) that can be expected for
different load currents. The curve also shows how the peak-
to-peak inductor ripple current (∆I
IND
) changes as you go
from the lower border to the upper border (for a given load
current) within an inductance region. The upper border rep-
resents a higher input voltage, while the lower border repre-
sents a lower input voltage (see Inductor Selection Guides).
These curves are only correct for continuous mode opera-
tion, and only if the inductor selection guides are used to
select the inductor value
Consider the following example:
V
OUT
= 5V, maximum load current of 2.5A
V
IN
= 12V, nominal, varying between 10V and 16V.
The selection guide in Figure 5 shows that the vertical line
for a 2.5A load current, and the horizontal line for the 12V
input voltage intersect approximately midway between the
upper and lower borders of the 33 µH inductance region. A
33 µH inductor will allow a peak-to-peak inductor current
(∆I
IND
) to flow that will be a percentage of the maximum load
current. Referring to Figure 21, follow the 2.5A line approxi-
mately midway into the inductance region, and read the
peak-to-peak inductor ripple current (∆I
IND
) on the left hand
axis (approximately 620 mA p-p).
As the input voltage increases to 16V, it approaches the
upper border of the inductance region, and the inductor
ripple current increases. Referring to the curve in Figure 21,
it can be seen that for a load current of 2.5A, the peak-to-
peak inductor ripple current (∆I
IND
) is 620 mA with 12V in,
and can range from 740 mA at the upper border (16V in) to
500 mA at the lower border (10V in).
Once the ∆I
IND
value is known, the following formulas can be
used to calculate additional information about the switching
regulator circuit.
1. Peak Inductor or peak switch current
2. Minimum load current before the circuit becomes dis-
continuous
3. Output Ripple Voltage = (∆I
IND
)x(ESR of C
OUT
)
= 0.62Ax0.1Ω=62 mV p-p
01258249
FIGURE 21. Peak-to-Peak Inductor
Ripple Current vs Load Current
LM2599
www.national.com27